a poleis broken at a height of 12 m from the ground and its top touches the ground at a distance of 35 m from the base of the pole due to the strong winds.find the original height of the pole
Answers
Answered by
21
solution of this question can be found using trigonometry
12m = opp side
35m = adjacent side
tan(theta)= opp side/adjacent side
theta = tan inv(opp side/adjacent side)
then sin(theta)= opp side/ hypotenuse
hypotenuse + opp side equals the original length of the pole
2nd method
assuming that the pole is making a right angeled triangle with the ground
Pythagoras theoram can be used to find the hypotenuse
then hypotenuse + opp side equals the original length of the pole
12m = opp side
35m = adjacent side
tan(theta)= opp side/adjacent side
theta = tan inv(opp side/adjacent side)
then sin(theta)= opp side/ hypotenuse
hypotenuse + opp side equals the original length of the pole
2nd method
assuming that the pole is making a right angeled triangle with the ground
Pythagoras theoram can be used to find the hypotenuse
then hypotenuse + opp side equals the original length of the pole
Answered by
16
12sqare +35 sqare u will get height sare of pole then
h = 37
Similar questions