If 1 is a zero of the polynomial p(x) =ax^2-3(a-1)x-1,then find the value of a
Answers
Answered by
15
if x=1 is a factor of p(x).
then a(1)2-3(a-1)(1)-1=0
2a-3a+3-1=0
-a=-3+1
-a=-2
so, a=2
then a(1)2-3(a-1)(1)-1=0
2a-3a+3-1=0
-a=-3+1
-a=-2
so, a=2
arbaas:
TFYA
Answered by
2
put x =1 in the function
u will get a =1
Similar questions