Math, asked by arbaas, 1 year ago

If 1 is a zero of the polynomial p(x) =ax^2-3(a-1)x-1,then find the value of a

Answers

Answered by sahilshamim1234
15
if x=1 is a factor of p(x).
then a(1)2-3(a-1)(1)-1=0
2a-3a+3-1=0
-a=-3+1
-a=-2
so, a=2

arbaas: TFYA
Vaishakachugvp: I meant a square not 2a
Answered by rhkashyap456
2

put x =1 in the function

u will get a =1


Vaishakachugvp: That's it
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