Question

cosecA-sinA=m and secA-cosA=n then prove that (m²n)⅔+(mn²)⅔=1​

Answer 1

Answer:

Please check the attachment for the solution.

Hope this helps you !

Answer 2

Answer:

sin²A +cos²A = 1

Step-by-step explanation:

cosecA-sinA=m

→1/sinA  sinA=m

→1-sin²A/sinA=m

→cos²A/sinA=m

similarly sin²A/cosA=n

(∛m²n)²=∛m power 4 n²

=∛cos power 8 A * sin power 4 A/sin power 4 A  * cos²A

=∛cos power 6 A

=cos²A

similarly (∛mn²)²=sin²A

and (∛m²n)²+(∛mn²) = sin²A+cos²A = 1

Hence,proved