(cosecA_SinA)(secA-CosA)=1/TanA +CotA
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Hey there!
LHS=(cosecA-sinA)(secA-cosA)
=(1/sinA – sinA )(1/cosA – cosA)
=[(1- sin2A)/sinA][(1-cos2A)/cosA]
=[(cos2A)/sinA][(sin2A)/cosA]
=sinA*cosA\/{sinA cosA}{sin^2A + cos^2A}
=1/sin^2A/sinA cosA + cos^2A/sinA cosA
=1/tanA + cotA
=RHS
Hence proved.
I hope it is clear!
Thanks!
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Please see the attached explanation
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