(cosecA-sinA) (secA-cosA) sec2A = tanA
Answers
Answered by
4
LHS= ( __1___ -sin A)(_____1____ - cosA) sec2A
sinA cosa
= (1 - sin2A/ sinA)(1-cos2A/cosA)sec2A
= (cos2A / sinA)(sin2A /cosA)(1+tan2A)
= sinA/cos A
=tanA
sinA cosa
= (1 - sin2A/ sinA)(1-cos2A/cosA)sec2A
= (cos2A / sinA)(sin2A /cosA)(1+tan2A)
= sinA/cos A
=tanA
aria02:
thank you
Answered by
11
Answer
Step by step explanation
Attachments:
Similar questions