Question

In a ΔPQR,if<P=30°,<Q=60°,then <R =.........
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Answer 1

Answer:

90⁰

Step-by-step explanation:

use Angle sum property

30+60+r=180⁰

transpose

90⁰+R=180⁰

R=180-90

R=90⁰

Answer 2

$\underline{\bigstar{\sf\ Given:-}}$

In a ΔPQR

<P=30°,<Q=60°

_________________

$\underline{\bigstar{\sf\ To\:Find:-}}$

<R

_________________

$\underline{\bigstar{\sf\ Solution:-}}$

<P + <Q + <R = 180°

[Angle sum property of a triangle]

30° + 60° + <R = 180°

90° + < R = 180°

<R = 180 - 90

<R = 90°

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