Math, asked by tomorrowmeans38, 11 months ago

(cosecA-sinA)(secA-cosA)(tanA+cotA)=?

Answers

Answered by khatwanisheetal6673

1

Answer:

(1/sinA-sinA)(1/cosA-cosA)(sinA/cosA+cosA/sinA)

(1-sin^2A/sinA)(1-cos^2A/cosA )(sin^2A+cos^2A/sinAcosA)

cos^2A/sinA×sin^2A/cosA×1/sinAcosA

=1

here is ur answer

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