Question

Three unbiased coins are tossed together . Find the probability of getting least two heads ?​

Answer 1

Answer:

$\frac{1}{2}$

Step-by-step explanation:

These are the probabilities

HHH

HHT

HTH

THH

HTT

THT

TTH

TTT

Total number of possible outcomes = 8

favourable outcomes= HHT   HTH   THH   HHH

P(getting atleast 2 heads)= $\frac{4}{8}=\frac{1}{2}$

HOPE IT IS HELPFUL !!

Answer 2

Answer:

1/2  or 0.5

Step-by-step explanation:

Possible outcomes:

HHH,  HHT,  HTH,  HTT

THH,   THT,   TTH,  TTT

Thus, the total number of possible outcomes: 8

Favourable outcomes: (At least two heads means two or more)

HHH,  HHT,  HTH,  THH

Thus, the total number of favourable outcomes: 4

Probability = 4/8

1/2  =  0.5