coseco-sino=m
seco - coso =n.
prove
(m²n2)2/3+(mn2)2/3=1
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Answer:
coseco - sino= m
1/sino -sino = m
(1- sin^2o)/sino = m
cos^2o/sino = m ........(1)
seco - coso = n
1/coso - coso = n
(1 - cos^2o)/coso = n
sin^2o/coso = n ..........(2)
now equation (1) multiply by equation (2) we get
mn =( cos^2o/sino ) × (sin^2o/coso)
= coso × sino
Step-by-step explanation:
something is missing in your question please reright your prove section
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