Question

coseco-sino=m
seco - coso =n.

prove

(m²n2)2/3+(mn2)2/3=1​

Answer 1

Answer:

coseco - sino= m

1/sino -sino = m

(1- sin^2o)/sino = m

cos^2o/sino = m ........(1)

seco - coso = n

1/coso - coso = n

(1 - cos^2o)/coso = n

sin^2o/coso = n ..........(2)

now equation (1) multiply by equation (2) we get

mn =( cos^2o/sino ) × (sin^2o/coso)

= coso × sino

Step-by-step explanation:

something is missing in your question please reright your prove section