Question

(cosectheta-sintheta) (secotheta-costheta) (tantheta + cottheta) =1
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Answer 1

Answer:

what do want to be proved please tell then only I can solve it easily

Answer 2

Step-by-step explanation:

let us use A in place of theta

so the ques will become

(cosec A-sin A)(sec A- cos A)(tan A+cot A)=1

((1/sin A)- sin A)((1/cos A)- cosA)((sinA/cosA)+(cos A/sin A)

$((1 - { \sin }^{2} a) \div sin \: a)((1 - { \cos }^{2} \: a) \div cos \: a)(( \ { \sin}^{2} a + \ { \cos }^{2}a ) \div (sin \: a \: cos \: a)) \\ ({cos}^{2} a \: {sin}^{2} a) \div ( {sin}^{2} a \: {cos}^{2} \\ = 1$

=RHS

PROVED

HOPE THIS WILL HELP YOU

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