Question

cosecx+sinx=26/25. evaluate sin2x+cosec2x . somebody plज़ help

Answer 1

ʜɪ ᴛʜᴇʀᴇ!

ʜᴇʀᴇ'ꜱ yᴏᴜʀ ᴀɴꜱᴡᴇʀ:-
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Given,

sin x + cosec x = 26/25

=> sin x + 1/sin x = 26/25

=> (sin^2 x + 1)/sin x = 26/25

=> sin^2 x + 1 = (26/25)*sin x

=> sin^2 x - (26/25)sin x + 1 = 0

=> (sin x - 26/25)sin x + 1 = 0

=> sin x + 1 = 0

=> sin x = - 1

Now,

sin^2 x + cosec^2 x
= sin^2 x + 1/sin^2 x

= (-1)^2 + 1/(-1)^2

= 1 + 1

= 2
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нσρє ιт нєℓρѕ! :-)

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