cospower 5 theta= A cos theta +B cos 3 theta+ C cos 5 theta
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If cos5θ=acosθ+bcos
3
θ+ccos
5
θ+d, then
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Solution
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Correct option is B)
cos5θ=cos(4θ+θ)=cos4θcosθ−sin4θsinθ=(2cos
2
θ−1)
2
−2sin2θcos2θsinθ
=[2(2cos
2
θ−1)
2
−1]cosθ−4sinθcosθ(2cos
2
θ−1)sinθ(2cos
2
θ−1)sinθ
=[2(4cos
2
θ−4cos
2
θ+1)−1]cosθ−4sin
2
θ(2cos
3
θ−cosθ)
=8cos
5
θ−8cos
3
θ+cosθ−4(1−cos
2
θ)(2cos
3
θ−cosθ)
=8cos
5
θ−8cos
3
θ+cosθ−4(2cos
3
θ−2cos
5
θ−cosθ)
=16cos
5
θ−20cos
3
θ+5cosθ
Hence, a=5,b=−20,c=16,d=0
∴a=b+c+d=1
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