Question

Cost of 10 oranges and 3 bananas is RS 109 and the cost of 3 oranges and 10 bananas is RS 60. Find the cost of 1orange and 1 banana

Answer 1

hi

Cost of 10 oranges and 3 bananas is RS 109

cost of 3 oranges and 10 bananas is RS 60

lest from some equations

10 oranges  + 3 bananas = 109...[1]

3 oranges +  10 bananas  = 60....[2]

now on adding [1]  and [2]

13 oranges + 13 bananas =  169

now let us divide all the 3 by 13

=> 1 orange + 1 banana  = rs13

hope it helps u

:)

Answer 2

Concept:

An algebraic expression in mathematics is an expression which is created from variables and constants, together with algebraic operations (addition, subtraction, etc.). Expressions are made of terms.

Given:

We are given cost of $10$ oranges and $3$ bananas is Rs $109$ and also the cost of $3$  oranges and $10$ bananas is Rs $60.$

Find:

we have to seek out the cost of $1$ orange and $1$ banana.

Solution:

Let the price of orange is Rs $x$ and also the cost of bananas is $y$.

According to the question,

$10x+3y=109 .......(1)\\3x+10y=60 ......(2)$

According to the question,

Now, we are going to find the worth of $x$ from equation $(2)$, we get

$x=\frac{60-10y}{3}$

Further, we'll substitute value of $x$ in equation (1), we get

$\begin{aligned}10\left(\frac{60-10y}{3}\right)+3y&=109\\ 200-\frac{100y}{3}+3y&=109\\ 91-\frac{91y}{3}&=0\\ 273&=91y\\ y&=3\end$

Furthermore, we are going to find the worth of  $x$ by substituting $y=3$, we get

$x=\frac{60-10\times 3}{3}\\ x&=10$

The total cost of $1$ orange and $1$ banana is $10+3=13$

Hence, the cost of $1$ orange is $10$ and cost of$1$ banana is $3$.

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