Cost of 21 bananas and 21 oranges put together is equal to 28 apples. Instead of
buying 21 bananas and 21 oranges, in the same cost if Sachin wants to buy equal
number of all three fruits, find how many apples can Sachin buy
please let me know the answer
Answers
Sachin can buy 12 Apples
Step-by-step explanation:
Cost of 1 Banana = B
Cost of 1 Orange = O
Cost of 1 Banana & 1 Orange together = B + O
Cost of 21 Banana & 21Orange together = 21(B + O)
Cost of 28 Apples = 21(B + O)
Cost of 1 Apple = 21(B + O)/28
=> Cost of 1 Apple = 3(B + O)/4
Let say Scahin buy F fruits of each type
Cost of F Banana & F Orange together = F(B + O)
Cost of F Apples = F3(B + O)/4
F(B + O) + F3(B + O)/4 = 21(B + O)
=> F + 3F/4 = 21
=> 4F + 3F = 84
=> 7F = 84
=> F = 12
12 Fruits of Each type
Sachin can buy 12 Apples
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Answer:
12
Step-by-step explanation:
Cost of 1 Banana = B
Cost of 1 Orange = O
Cost of 1 Banana & 1 Orange together = B + O
Cost of 21 Banana & 21Orange together = 21(B + O)
Cost of 28 Apples = 21(B + O)
Cost of 1 Apple = 21(B + O)/28
=> Cost of 1 Apple = 3(B + O)/4
Let say Scahin buy F fruits of each type
Cost of F Banana & F Orange together = F(B + O)
Cost of F Apples = F3(B + O)/4
F(B + O) + F3(B + O)/4 = 21(B + O)
=> F + 3F/4 = 21
=> 4F + 3F = 84
=> 7F = 84
=> F = 12
12 Fruits of Each type
Sachin can buy 12 Apples