cost of 3kg apples and 3 kg oranges are rupees270. let the cost of 1kg of apple be rupees 'x' and the cost of 1kg of oranges be rupees 'y'. write the given data in the form of a linear equation in 2 variables. also represent it graphically
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Answer:
The linear equation which satisfy is x + y = 90 .
Step-by-step explanation:
Given as :
Given as :
Total cost of 3 kg apple and 3 kg orange = Rs 270
The cost of 1 kg apple = Rs x
So, The cost of 3 kg apple = Rs x × 3
Or, The cost of 3 kg apple = Rs 3 x
Again
The cost of 1 kg orange = Rs y
So, The cost of 3 kg orange = Rs y × 3
Or, The cost of 3 kg orange = Rs 3 y
Now,
The linear equation which relate
Rs 3 x + Rs 3 y = Rs 270
i.e 3 x + 3 y = 270
or, x + y =
∴ x + y = 90
Hence, The linear equation which satisfy is x + y = 90 . Answer
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cost of 3kg apples and 3 kg oranges are rupees270. let the cost of 1kg of apple be rupees 'x' and the cost of 1kg of oranges be rupees 'y'. write the given data in the form of a linear equation in 2 variables. also represent it graphically.
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