Question

cost of 3kg apples and 3 kg oranges are rupees270. let the cost of 1kg of apple be rupees 'x' and the cost of 1kg of oranges be rupees 'y'. write the given data in the form of a linear equation in 2 variables. also represent it graphically

Answer 1

Answer:

The linear equation which satisfy is x + y = 90 .

Step-by-step explanation:

Given as :

Given as :

Total cost of 3 kg apple and 3 kg orange = Rs 270

The cost of 1 kg apple = Rs x

So, The cost of 3 kg apple  = Rs x × 3

Or, The cost of 3 kg apple  = Rs 3 x  

Again

The cost of 1 kg orange = Rs y

So, The cost of 3 kg orange  = Rs y × 3

Or, The cost of 3 kg orange  = Rs 3 y

Now,

The linear equation which relate

Rs 3 x + Rs 3 y = Rs 270

i.e  3 x + 3 y = 270

or,  x + y = $\dfrac{270}{3}$

∴   x + y = 90

Hence, The linear equation which satisfy is x + y = 90 . Answer

Answer 2

cost of 3kg apples and 3 kg oranges are rupees270. let the cost of 1kg of apple be rupees 'x' and the cost of 1kg of oranges be rupees 'y'. write the given data in the form of a linear equation in 2 variables. also represent it graphically.

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