Cost price of article A and B are rupees 100 and rupees X respectively. The profit percent of article A and B are 20% and 25% respectively .If SP of article A is less than article B by 280 rupees . find the value of X.
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The price of articles A & B are Rs. 350 and Rs. 400 respectively. Article A was sold at a profit of 10% and article B was sold at a loss of X%. If the overall loss incurred after selling both the articles is Rs. 109, what is the value of X?
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Surbhi Tewatia
, Math Expert at
Cost price of A=Rs. 350
Cost price of B=Rs.400
Total C.P=Rs.750
There is profit of 10 percent on A,So S.P=(350*110)/(100)=385.
There is loss of x percent on B,So S.P=(400*(100-x))/(100)=4(100-x)
Total S.P=385+4(100-x)=785–4x
So now its given that overall loss is incured,
Total C.P >Total S.P
Loss =C.P-S.P
=750-(785–4x)
=-35+4x
Hence 109=-35+4x
x=36
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Answer:
From the given data,following interpretation is done,
Cost price of A and B is “x”
Profit percent for article A is 10
Profit percent for article B is 30
So,
10% of x + 30% of x = 136,which is the total profit
(10x/100) + (30x/100) = 136
40x/100 = 136
40x = 136 × 100
x = (136 × 100) / 40
x = 340
Cost price of article A and B is 340
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