Question

Cost Price of two motorcycles is same. One is sold at a profit of 15% and the other for Rs. 4800 more than the first. If the net profit is 20%. Find the cost price of each motorcycle

Answer 1

Answer: 48000

Step-by-step explanation:

Let the CP of each motorcycle be Rs. n then

(2 x 1.15 x n) + 4800 = 2 x 1.2 x n

⇒ 0.1 x n = 4800

∴ Rs = 48000

Answer 2

The cost price of each motorcycles is 48000 rupees.

Step-by-step explanation:

Consider the provided information.

Cost Price of two motorcycles is same.

The average profit or net profit is 20%.

Let p represents the profit of second bike.

$\frac{15+p}{2}=20\\p+15= 40\\p=25$

That means profit on second bike must be 25%.

It is given that One is sold at a profit of 15% and the other for Rs. 4800 more than the first.

That means the difference of profit percentage must be equal to 4800.

25%-15%=10%

10% of x = 4800

Where x is the cost price of motorcycle.

$\frac{10}{100}\times x=4800\\ x=\frac{4800}{0.1}\\ x=48000$

Hence, the cost price of each motorcycles is 48000 rupees.

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