Math, asked by ruchitpatel6213, 1 year ago

Costeeta+cos(120dgree+teeta)+cos(120dgree+teeta)=0

Answers

Answered by waqarsd
0

Answer:

cos\theta + cos(120^0 +\theta) +cos(120^0-\theta)=0

Step-by-step explanation:

cos\theta + cos(120^0 +\theta) +cos(120^0-\theta)\\cos\theta+(cos120^0cos\theta-sin120^0sin\theta)+(cos120^0cos\theta+sin120^0sin\theta)\\cos\theta+2cos120^0cos\theta\\cos\theta-cos\theta\\0\\since\\cos(A+B)=cosAcosB-sinAsinB\\cos(A-B)=cosAcosB+sinAsinB\\cos120^0=\frac{-1}{2}

Hope It Helps

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