costheta/1-sintheta+costheta/1+sintheta
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Step-by-step explanation:
Let theta be A .
cosA /(1-sinA) + cosA/(1+sinA)
=cosA(1+sinA)/(1+sinA)(1-sinA). + cosA(1-sinA)/(1+sinA)(1-sinA)
=( cosA+cosAsinA)/(1-sin^2A)
+(cosA-cosAsinA)/(1-sin^2A)
= (cosA+cosAsinA+cosA-cosAsinA)/(1-sin^2A)
= 2cosA/cos^2A
[since , sin^2A + cos^2A = 1
→1-sin^2A = cos^2A ]
= 2/cosA
= 2secA
=2sec theta
SushritaSingh:
but how?
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