Question

costheta-sintheta/costheta+sintheta=1-root3/1-root3​

Answer 1

cos∅-sin∅/cos&+sin∅=cot∅

Step-by-step explanation:

LHS=cos∅-sin∅/cos&+sin∅

=(cos∅-sin∅) (cos∅-sin∅) /(cos∅+sin∅) (cos∅-sin∅)

=cos²∅-2cos∅sin∅+sin²∅/cos²∅-sin²∅

=1-2cos∅sin∅/1-sin²∅-sin²∅

=1-2cos∅sin∅/1-2sin²∅

=cos∅/sin∅

=cot∅

=RHS