Question

Costruct a quadrilateral PQRS in which, PQ=5.5 , PS = 6 cm, Angle S = 90° = Angle Q and Angle R =100° .​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

draw party 5.5 cm with scale

mark starting and ending point as possible and q

take compass mark an arc as center p

as told angle s = q so draw 90 degree angle with compass

as center q draw a semi circle smaller than half of PQ the point on which your semi circle arc and line PQ met name e as centre e draw an arc of the same distance of e and q name f to point where arc and semi circle arc meet draw another arc of same distance from f at upper side and on semi circle arc also name this intersection point as good and now draw anc with again same distance at upper side two arc at upper side of f and g intersect grow an line from q running through this intersection point your 90 degree angle is constructed at q

three angle are 90 , 90 , 100 than p will be 360 _ ( 90+90+100) = 80

draw 90 degree angle at practice with protector extent line ps the arc s will intersection with it here again make 90 degree angle

and extend line sr

your quadrilateral pqrs is constructed

dear it's first time I answered

for any mistake please sorry

hope it is helping for you