cosx/1-sinx + cosx/1+sinx = 4
answ plsz
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x=60degree
by taking LCM and apply trigonometric rules..
by taking LCM and apply trigonometric rules..
parulsh:
why x is taken as 60 degree ? sorry i didn't get the concept
cosx*(1+sinx+1-sinx)/(1-sin^2x)=4. now 2cosx/cos^2x=4.and .cosx=1/2.so x=60 degree. we know 1-sin^2x =co^2x and cos 60 = 1/2..
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cos(x)/1 - sin(x) +cos(x)/1+sin(x) = 4
cos(x){1 + sin(x) + 1 - sin(x)}/(i - sin(x))(1 + sin(x)) = 4
cos(x) {2}/ (1 - sin^2(x)) = 4
cos(x)/cos^2(x) = 4
cos(x) = 1/2
x =2n pi +- pi/3
cos(x){1 + sin(x) + 1 - sin(x)}/(i - sin(x))(1 + sin(x)) = 4
cos(x) {2}/ (1 - sin^2(x)) = 4
cos(x)/cos^2(x) = 4
cos(x) = 1/2
x =2n pi +- pi/3
sorry my english is very poor
cos fair equation i did't get.
i can send you that lesson
u r right Wishwa
thanks bro
that is general solution..
sorry i have not study in maths english medium
extremely sorry
we got it..don't say sorry..
ok
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