Question

two bills of rs 6075 and rs.8505 respectively are to the paid by chequs of the same amount . what will be the larget possible amount of each cheques?

Answer 1

6075=5*5*3*3*3*3*3
8505=5*3*3*3*3*3*7
therfore the HCF of 6075 and 8505 = 5*3*3*3*3*3
                                                              =5*243
                                                               =1215
Thus the maximum possible ammount of each cheque is 1215 rs.

Answer 2

Answer:

The larget possible amount of each cheques is 1215

Step-by-step explanation:

• The complete form of HCF is Highest Common Factor.
• HCF of numbers is the best component which can divide the 2 numbers, evenly.
• HCF may be evaluated for 2 or greater than numbers. It is the finest divisor for any or greater numbers, which can similarly or absolutely divide the given numbers

This is an HCF question

Factors of 6075 : 5×5×3×3×3×3×3

Factors of 8505:5×3×3×3×3×3×7

HCF of 6075 and 8505 is = 5×3×3×3×3×3

= 5× 243

= 1215

The larget possible amount of each cheques is 1215.

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