cosX + cosY = 2 then sinX + sinY
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sinx+siny=2
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answer is 0
we know that maximum value of cosx is 1
so for getting 2,
it should be cosx + cos y =2
1+1 =2
cos0 + cos0 =2
so ,sinx+ siny = sin0+ sin0 =0
remember one thing, cos can have only the maximum value 1 (when theetta=nπ)
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