Math, asked by Imsaki71691, 4 months ago

Cosy- siny= answer this plz
Anybody.......

Answers

Answered by maximusop56900
0

Answer:

 \sqrt{2 \: sin}

Answered by Anonymous
0

Answer:

Trigonometric Functions of Acute Angles

sin X = opp / hyp = a / c , csc X = hyp / opp = c / a

tan X = opp / adj = a / b , cot X = adj / opp = b / a

cos X = adj / hyp = b / c , sec X = hyp / adj = c / b ,

acute angle trigonometric functions.

Trigonometric Functions of Arbitrary Angles

sin X = b / r , csc X = r / b

tan X = b / a , cot X = a / b

cos X = a / r , sec X = r / a

acute angle trigonometric functions.

Special Triangles

Special triangles may be used to find trigonometric functions of special angles: 30, 45 and 60 degress.

special triangles.

Sine and Cosine Laws in Triangles

In any triangle we have:

1 - The sine law

sin A / a = sin B / b = sin C / c

2 - The cosine laws

a

2 = b 2 + c 2 - 2 b c cos A

b 2 = a 2 + c 2 - 2 a c cos B

c 2 = a 2 + b 2 - 2 a b cos C

triangles.

Relations Between Trigonometric Functions

cscX = 1 / sinX

sinX = 1 / cscX

secX = 1 / cosX

cosX = 1 / secX

tanX = 1 / cotX

cotX = 1 / tanX

tanX = sinX / cosX

cotX = cosX / sinX

Pythagorean Identities

sin 2X + cos 2X = 1

1 + tan 2X = sec 2X

1 + cot 2X = csc 2X

Negative Angle Identities

sin(-X) = - sinX , odd function

csc(-X) = - cscX , odd function

cos(-X) = cosX , even function

sec(-X) = secX , even function

tan(-X) = - tanX , odd function

cot(-X) = - cotX , odd function

Cofunctions Identities

sin(π/2 - X) = cosX

cos(π/2 - X) = sinX

tan(π/2 - X) = cotX

cot(π/2 - X) = tanX

sec(π/2 - X) = cscX

csc(π/2 - X) = secX

Step-by-step explanation:

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