Question

cot⁻¹(1)+ 3sin⁻¹ 1/2 -cosec⁻¹(-2)- 3tan⁻¹ 1/√3, Find value of it.

Answer 1

Step-by-step explanation:

hey mate it takes too much time so idk sorry

Answer 2

Answer:

$\frac{5\pi}{12}$

Step-by-step explanation:

just putting the value in radians and solving it

$cot^{-1}(1)=\frac{\pi}{4}$

$sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$

$cosec^{-1}(-2)=-\frac{\pi}{6}$

$tan^{-1}(\frac{1}{\sqrt{3}})=\frac{\pi}{6}$

therefore given equation becomes

$\frac{\pi}{4}+3\times\frac{\pi}{6}+\frac{\pi}{6}-3\times\frac{\pi}{6}$

$\frac{\pi}{4}+\frac{\pi}{2}+\frac{\pi}{6}-\frac{\pi}{2}$

$5\times\frac{\pi}{12}$

=$5\frac{\pi}{12}$