cot^2 theta (1-cos^2theta)=cos^2theta
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Step-by-step explanation:
We know, cot theta = cos theta/sin theta
=) cot∧2 theta = cos∧2 theta/sin∧2 theta.
and sin∧2 theta + cos∧2 theta = 1
=)sin∧2 theta = 1 - cos∧2 theta.
Now solving the question,
with taking L.H.S ;
=) cos∧2 theta/sin∧2 theta × (1 - cos^2 theta)
=) cos∧2 theta/sin∧2 theta × sin∧2 theta
=) cos∧2 theta. (here 1/sin∧2 theta and sin∧2 theta are cancelled)
hence proved.
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hope this will help uh ...
nd plz mark as brainliest ...
nd plz mark as brainliest ...
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