Question

cot 3π/8 ka man ho hoga​

Answer 1

Answer:

(1/2)√(2-√2)

Step-by-step explanation:

cos(3π/8)

= (1/√2) √2cos²(3π/8)

= (1/√2)√[cos(3π/4) +1]

= (1/√2)√[cos(π/2+π/4)+1]

= (1/√2)√[ - sin(π/4) +1]

= (1/√2)√[ (-1/√2)+1]

= (1/√2)√ [( √2-1)/√2]

= (1/√2) √ [(2 -√2 )/2]

= (1/2)√ (2-√2)

Hope this helps you

formula used

(1) 2cos²x = cos(2x) +1

(2) cos(π/2+x) = - sinx

Answer 2

Answer:

√2-1

Formula Used;

tanA/2 = (1-cosA)/sinA

Step-by-step explanation:

(i) cot(3π/8)→ tan(π/2-3π/8)→ tan(π/8)

(ii) tan(π/8)= [1-cos(π/4)]/[sinπ/4]

tan(π/8)=[(√2-1)/√2]/(1/√2)

tan(π/8)= √2-1

Hope It Helps!