cotФ=4/3, then P.T 1+sinФ/1+cosФ*1-sinФ/1-cosФ=16/9
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Cot Ф=4/3=base/prependiculat
hypo=5
ATQ..................
1+sinФ/1+cosФ 1-sinФ/1-cosФ
1+3/5 1-3/5
1+4/5 1-4/5
8/9 x 2/1=16/9
hypo=5
ATQ..................
1+sinФ/1+cosФ 1-sinФ/1-cosФ
1+3/5 1-3/5
1+4/5 1-4/5
8/9 x 2/1=16/9
nitheeshadasa:
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L.H.S
1+SinФ/1+CosФ *1-SinФ/1-CosФ ;
1-Sin^2Ф/1-Cos^2Ф [by identity sin^2Ф+ cos^2Ф=1] ;
Cos^2Ф/Sin^2Ф ;
Cot^2Ф ;
(4/3)^2 ;
16/9
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