Question

[cot (π/4 - theta) - 1](cot theta–1)​

Answer 1

Answer:

GIVEN THAT :–

$= (\cot( \frac{\pi}{4} - \alpha ) - 1)( \cot( \alpha ) - 1 )$

WE KNOW THAT –

$\cot( \alpha - \beta ) = \frac{ \cot( \alpha ) \cot( \beta ) + 1}{ \cot( \beta ) - \cot( \alpha ) }$

SO THAT –

$= (\frac{ \cot( \alpha ) + 1 }{ \cot( \alpha ) - 1} - 1)( \cot( \alpha ) - 1) \\ \\ = ( \frac{2}{ \cot( \alpha ) - 1 } )( \cot( \alpha ) - 1) \\ \\ = 2$

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Answer 2

Step-by-step explanation:

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