Math, asked by divyanshu36985, 9 months ago

cot 4x(sin 5x + sin 3x) = cot x(sin 5x - sin 3x)​

Answers

Answered by saumya5476
4

taking LHS

= Cot 4x (2 sin 5x+3x/2 × cos5x-3x/2)

= cot 4x (2 sin4x cosx)

= cos 4x/sin4x ×2 sin4x cosx

= 2cos4x cosx

taking RHS

= cotx (2 cos 5x+3x/2 sin 5x-3x/2)

= cotx (2 cos4x sinx )

= cosx/sinx ×2 cos4x sinx

= 2 cos4x cosx

Hence,

LHS = RHS

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