Question

Cot A = 12/5 , sin A+ cos B =

Answer 1

Answer:

sinA+ cos B =5/13+12/13

=17/13

Step-by-step explanation:

draw a triangle by the given data and find sinA and cos A

Answer 2

ok so the question given here is Cot A =12/5    

find Sin A+cosB

so we know cot A=adjacent side /

                                opposite side and Angle c is 90 ,

so side AC=12 cm ,CB=5 cm ,AB=?          (refer attachment )

using pythagoras theorem  we get side AB to be root of 12^2+5^2

=13 cm so

finding the values

sin A=opposite side/       =CB/    =5/

          hyypotenuse           AB       13

cos B=adjacent/          =CB/      =5 /

          hypotenuse        AB          13

sin A+cos B=5/13+5/13=10/13

actually you might wonder why sin A and cos B are same ?

the reason is due to complementary angles sin (A)=cos(90-A)

in right triangles right angled at C

angle A+angle B=90

so angle A can be writen as 90-angle b

due to this relation ship

sin A=cos B

hope you understand (●'◡'●)