Question

cot a- tan a=2 cos2a-1/sina.cosa

Answer 1

нєℓℓσ ∂єαя υѕєя!!!!


нєяє ιѕ уσυя αиѕωєя тнαт уσυ αяє ωαιтιиg fσя... :


αиѕωєя:


Given;

=>(cos A / sin A) - (sin A / cos A)

=> (cos²A - sin²A) / (sin A cos A)

=> [ cos²A - (1 - cos²A)] / (sin A cos A)

(Since sin²Θ = 1 - cos²Θ )

=> (co²A - 1 + cosA) / (sin A cos A)

=> (2 cos²A - 1) / (sin A cos A)


Therefore LHS = RHS

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ι нσρє тнιѕ ωιℓℓ нєℓρѕ уσυ....... :)


нανє α gяєαт ∂αу αнєα∂....... ^_^


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