Question

cot B=y/x then sin B ​

Answer 1

Answer:

sinB = x/x²+y²

Step-by-step explanation:

Given cotB= y/x= Base/Perpendicular

Base = y Perpendicular= x

(Hypotenuse)²= (Base)²+(Perpendicular)²

H= x²+y²

SinB= Perpendicular/Hypotenuse

SinB= x/(x²+y²)