cot(C)/(2)=(s(s-c))/(Delta)
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Answer:
:
A2+B2=π2−C2
cot(A2+B2)=cot(π2−C2)=tanC2=1cotC2
Apply cot(x+y)=cotxcoty−1cotx+coty
Step-by-step explanation:
It shouldn't be that hard cause you have this two.
cos(A2)sin(A2)+cos(B2)sin(B2)+cos(C2)sin(C2)=cos(A2)sin(A2)×cos(B2)sin(B2)×cos(C2)sin(C2)
A+B+C=180
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