Question

cot(sin‐1 3/4 + sec-1 4/3)​

Answer 1

Answer:

(16/21)√7

Step-by-step explanation:

cot( sin inverse3/4+ sec inverse 4/3)

= cot( cot inverse(√4²-3²)/3 + cot inverse 3/(√4²-3²)

= cot( cot incerse√7/3+ cot inverse3/√7)

= √7/3+3/√7

= (7+9) / 3√7

= (16/21) √7

hope this helps you

Answer 2

$\large{\red{\underline{\tt{Solution}}}}$

=cot (-1 $\sf\dfrac{3}{4}$ + sec -1 $\sf\dfrac{4}{3}$ )

= cot ( sin -1$\sf\dfrac{3}{4}$ + cos -1$\sf\dfrac{3}{4}$

[∴ sec^-1x = cos^-1$\sf\dfrac{1}{x}$ ]

= cot ($\sf\dfrac{π}{2}$)

$\implies\rm 0$