Question

one number is 7 more than another and its square is 77 more than the square of the smaller number what is the number​

Answer 1

Let 1st number be A and 2nd number be B

According to question:

B-A= 7

B=7+A

AND

B^2-A^2= 77

Now put the above equation and find the answer

Answer 2

Answer:

the number is 2

Step-by-step explanation:

Let the smaller number be x

Let the greater number be x+7

according to the question,

77+x² =(x+7)²

77+x²= x² +49+14x

77-49 =14x

28 =14x

x= 2