Question

cot[sin^-1 3/5+cot^-1 3/2​

Answer 1

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Answer 2

Solution

$tan \: (sin - 1 \frac{3}{5} + cot - 1 \frac{3}{2} )$

$= tan \: (tan - 1 \frac{3}{4} + tan - 1 \frac{2}{3} )$

$= tan(tan - 1 \frac{3}{4} + \frac{2}{3}\1 - \frac{3}{4} . \frac{2}{3} )$

$= tan \: (tan - 1 \frac{9 + 8}{12 - 6} )$

$= tan \: (tan - 1 \frac{17}{6}) = \frac{17}{6}$