Math, asked by banakarrohit1, 3 months ago

cot square π/6-2cos square π/3-sec square π/4-4sin square π/6 find the vale​

Answers

Answered by Snapskg730
4

Answer:

 \cot  {}^{2} \frac{\pi}{6}  - 2 \cos {}^{2} \frac{\pi}{3} -  \sec {}^{2}  \frac{\pi}{4} - 4 \sin {}^{2} \frac{\pi}{6}

 \cot {}^{2}30 - 2 \cos {}^{2}60 -  \sec {}^{2}45 - 4 \sin {}^{2} 30

 (\sqrt{3} ) {}^{2}  - 2 \times ( \frac{1}{2} ) {}^{2}  - ( \sqrt{2} )  {}^{2}  - 4 \times ( \frac{1}{2} ) {}^{2}

3 \:  -  \:  \frac{1}{2}  - 2 \:  - 4 \times  \frac{1}{4}

3 -  \frac{1}{2}  - 2 - 1

 \frac{6 - 1 - 4 - 2}{2}

 -  \frac{1}{2}

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