Cot square-tan square =cosec square-sec square
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question as it is
cosec²x-sec²x=cot²x-tan²x
=cosec²-1-tan²x
=cosec²x-(sec²x)
=cosec²x-sec²x
x=teta
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(a²-b²)²+(a²+b²)²
=>Expanding both of them we get,
(a⁴+b⁴-2a²b²) + (a⁴+b⁴+2a²b²)
Hence, on opening the brackets...
It gives, 2(a⁴+b⁴)
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