Question

cot theta-cos theta/cos theta + cos theta is= sec^2 theta - 2 cos theta + cot^2 theta​

Answer 1

$\bold {ax}^{2} + \bold {bx} \: + \bold c \: = \bold 0 \\ \\ \bold {sin \alpha \times cos \alpha} = \bold {\frac{ - b}{a} } \\ \\ \bold {sin \alpha \times cos \alpha} = \bold {\frac{c}{a}} \\ \\ \bold {(sin \alpha + cos \alpha )^{2}} = \bold {{sin}^{2} \alpha + 2sin \times cos \alpha + \: {cos}^{2} \alpha} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \: = \bold {{sin}^{2} \alpha + {cos}^{2} \alpha + 2sin \times cos \alpha} \\ \\ \bold {( \frac{ - b}{a})^{2}} = \bold {1 + \frac{2c}{a}} \\ \\ \bold {\frac{ {b}^{2} }{ {a}^{2} }} \: = \bold {1 + \frac{2c}{a}} \\ \\ \bold {{b}^{2}} = \bold {\frac{ {a}^{2}(a + 2c) }{a}} \\ \\ \bold {{b}^{2}} = \: \bold {{a}^{2}} + \: \bold {2ac}$

Answer 2

Answer:

♦ Wall painted by Malala = \bold{\frac{7}{12}}

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7

♦ Wall painted by Geetha = \bold{\frac{21}{36}}

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♦ \bold{\frac{21}{36}}

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be also written as \bold{\frac{7}{12}}

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♦ So in this way they both painted same fraction of the wall i.e. \bold{\frac{7}{12}}

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7

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