Question

find the area of squares whoose :(a)side=8(b)diagonal=5.2cm

Answer 1

hello mate ,
HERE is the answer
____________________

(a)
area of square of side 8 cm
area = 8 ×8 = 64 sq. cm
(b)

diagonal =5.2cm
area = 1/2 × 5.2 ×5.2
= 13.52 sq. cm

_______________
hope this helps you
please like it and
$mark \: \: as \: \: brainlist$
TH@NkS

Answer 2

hey mate
here is answer
__________

area of square formula
${(side)}^{2}$
and
$\frac{1}{2} \times {(diagonal)}^{2}$
(a)
${(8)}^{2} {cm}^{2}$
$64 {cm}^{2}$
(b)
$\frac{1}{2} \times {(5.2)}^{2} {cm}^{2}$
$13.52 {cm}^{2}$