Question

(cot theta/cot theta -cot3theta) + ( tan theta/tan theta -tan 3theta) is equal to?​

Answer 1

Answer:it was very tough yar, hope it ll help u.

Step-by-step explanation:

Answer 2

Cotθ  /( Cotθ - Cot³θ)   + Tanθ  /( Tanθ - Tan³θ)  = 1

Step-by-step explanation:

Cotθ  /( Cotθ - Cot³θ)   + Tanθ  /( Tanθ - Tan³θ)

= Cotθ  /( Cotθ(1  - Cot²θ))   + Tanθ  /( Tanθ(1  - Tan²θ) )

= 1/(1  - Cot²θ)  + 1/(1  - Tan²θ)

= 1/(1  - Cos²θ/Sin²θ)  + 1/(1 - Sin²θ/Cos²θ)

= Sin²θ/(Sin²θ - Cos²θ)  + Cos²θ/(Cos²θ  - Sin²θ)

= Sin²θ/(Sin²θ - Cos²θ)  - Cos²θ/(Sin²θ  - Cos²θ)

= (Sin²θ - Cos²θ)/(Sin²θ - Cos²θ)

= 1

Cotθ  /( Cotθ - Cot³θ)   + Tanθ  /( Tanθ - Tan³θ)  = 1

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