Cot theta tan(90°-theta)-sec(90°-theta) cosec theta+sin square65°+sin square25°+ root3tan5° tan85°
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Your question:- Evaluate cot theta .tan(90- theta)-sec(90- theta) cosec theta + ( sin 2 35 + sin 2 55) + root 3(tan 5.tan 15.tan 30 .tan 75.tan 85)
Answer:- Cotθ.tan(90°-θ)-sec(90°-θ)cosecθ+(sin²35°+sin²55°) +√3(tan5°.tan15°.tan30°.tan75°.tan85°)
=cotθ.cotθ-cosecθ.cosecθ+sin²35°+sin²(90°-35°)+√3{tan5°.tan15°.(1/√3).
tan(90°-15°).tan(90°-5°)}
=cot²θ-cosec²θ+sin²35°+cos²35°+√3×1/√3(tan5°tan15°cot15°cot5°)
=-1+1+{tan5°tan15°(1/tan15°)(1/tan5°)}
=1
Answer:- Cotθ.tan(90°-θ)-sec(90°-θ)cosecθ+(sin²35°+sin²55°) +√3(tan5°.tan15°.tan30°.tan75°.tan85°)
=cotθ.cotθ-cosecθ.cosecθ+sin²35°+sin²(90°-35°)+√3{tan5°.tan15°.(1/√3).
tan(90°-15°).tan(90°-5°)}
=cot²θ-cosec²θ+sin²35°+cos²35°+√3×1/√3(tan5°tan15°cot15°cot5°)
=-1+1+{tan5°tan15°(1/tan15°)(1/tan5°)}
=1
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Answer:
hey mate here is ur CORRECT ans
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