Question

cot theta + tan theta = sec theta Cosec theta​

Answer 1

hope this helps you.. :)

Answer 2

hey brainly

simple

let theta =a

now l.h.s

=cota+tana

=cosa/sina+sina/cosa

=cosa(cosa)+sina(sina)/sinacosa

cos*2a+sin*2a/sinacosa

1/sina cosa

=(1/sina)1/cosa

=(coseca)(secs)

l.h.s=r.h.s

hence proved