Cot18°[cot 72°•cos square 22°+1/tan72°•sec square 68°]
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Answer:
1
Step-by-step explanation:
Given Cot18°[cot 72°•cos square 22°+1/tan72°•sec square 68°]
We need to find the given expression
So we get
cot 18 x cot 72 x cos^2 22 + cot 18 / tan 72 x sec^2 68
cot 18 x cot(90 - 18) x cos^2 22 + cot 18 / tan (90 - 18) x cos^2 68
cot 18 x tan 18 x cos^2 22 + cot 18 / cot 18 x cos^2 68
cos ^2 22 + cos^2 (90 - 22)
cos^2 22 + sin^2 2
= 1
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