cot57/tan63-tan27/cot33,answer this people
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To find :
The value of ( cot 57 / tan 63 ) - ( tan 27 / cot 33 )
Solution :
We know , tan ( 90 - θ ) = cot θ
and , cot ( 90 - θ ) = tan θ
we can write , cot 57 = tan ( 90 - 57 ) = tan 33
and , tan 63 = cot ( 90 - 63 ) = cot 27
now ,
( cot 57 / tan 63 ) - ( tan 27 / cot 33 )
→ ( tan 33 / cot 27 ) - ( tan 27 / cot 33 )
→ [ ( tan 33 * cot 33 ) - ( tan 27 * cot 27 ) ] / ( cot 33 * cot 27 )
→ ( 1 - 1 ) / ( cot 33 * cot 27 )
→ 0 / ( cot 33 * cot 27 )
→ 0
The value of ( cot 57 / tan 63 ) - ( tan 27 / cot 33 ) is 0 .
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