Question

cot6A-tan2A/cot6A+tan2A=cos8A/cos4A​

Answer 1

Answer:

cos 6A /sin 6A -sin 2A/cos 2A

______________________________

cos 6A/sin 6A+ sin 2A/cos2A

cos6A cos2A-sin6A sin2A

__________________________

cos 6A cos2A+ sin 6A sin 2A

cos(6A+2A)

____________

cos(6A-2A)

cos8A/cos2A

Answer 2

• Answer:
• cos6A/sin6A - sin2A/cos2A
• cos6A/sin6A - sin2A/cos2Acos6A/sin6A + sin2A/cos2A

• cos6A.cos2A - sin6A.sin2A
• cos6A.cos2A + sin6A.sin2A

• cos(6A+2A)
• cos(6A-2A)

• cos8A
• cos4A
• (hence proved)