Question

cotA-1/2sec²A=cotA/1+tanA​

Answer 1

Step-by-step explanation:

LHS = (CotA -1) /( 2- Sec²A )

= ( CotA-1) / (1 + 1 - Sec²A)

= (1/tanA)-1 / ( 1 - tan²A) ●Since tan²A +1 = sec²A So, 1- Sec²A = - tan²A

= (1-tanA) / tanA (1+tanA)(1-tanA) ● by identity a² -b² = (a+b) ( a-b)

= 1/ tanA(1+tanA)

= CotA / (1+tanA) = RHS

[ Hence Proved]

Answer 2

Answer:

LHS=cotA−12−sec2A

=1tanA−12−(1+tan2A)

=1−tanAtanA1−tan2A

=1−tanAtanA(1−tan2A)

=1−tanAtanA(1−tanA)(1+tanA)

=1tanA(1+tanA)

=cotA

1+tan A

=RHS

Step-by-step explanation:

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