Question

cotA(1+sinA)=m and cotA(1-sinA) =n find mn.​

Answer 1

Step-by-step explanation:

If cotA(1+sinA)=m and cotA(1-sinA) =n then we have,

=mn=cotA(1+sinA) ×cotA(1-sinA)

=mn=cot^2A(1-sin^2A)

=mn=cot^2A×cos^2A

=or mn=cos^4A/sin^2A

Answer 2

Answer:

cosA square.cotA square

Step-by-step explanation:

m = cotA( 1+ sinA)

n = cotA ( 1 - sinA)

find mn

so we do

cot A ( 1 + sinA ) cot A ( 1 - sinA) = mn

cotA square ( 1 - sinA square )

cot A square cos A square

i hope it helps you